PHP | Imagick displayImage() Function

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The Imagick::displayImage() function is an inbuilt function in PHP which is used to displays an image object.

Syntax:

bool Imagick::displayImage( $servername )

Parameters: This function accepts a single parameter $servername which is used to specify the server name.

Return Value: This function returns True on success.

Below programs illustrate the Imagick::displayImage() function in PHP:

Program:

<?php 
  
// Create an Imagick object 
$imagick = new Imagick( 
'https://media.zambiatek.com/wp-content/uploads/zambiatek-9.png'); 
  
// Use displayImage function 
$imagick->displayImage(5); 
  
header("Content-Type: image/jpg"); 
  
// Display the output image 
echo $imagick->getImageBlob(); 
?> 

Output:

Program 2:

<?php 
$string = "Computer Science portal for Geeks!"; 
  
// creating new image of above String  
// and add color and background  
$im = new Imagick(); 
$draw = new ImagickDraw(); 
  
// Fill the color in image  
$draw->setFillColor(new ImagickPixel('green')); 
  
// Set the text font size  
$draw->setFontSize(50); 
  
$matrix = $im->queryFontMetrics($draw, $string); 
$draw->annotation(0, 40, $string); 
$im->newImage($matrix['textWidth'], $matrix['textHeight'], 
         new ImagickPixel('white')); 
  
// Draw the image           
$im->drawImage($draw); 
  
$im->setImageFormat('jpeg'); 
  
header("Content-Type: image/jpg"); 
  
// Display the output image 
echo $im->getImageBlob(); 
?> 